• (1)已知a=8,b=-2,求[a-12b(ab-2)-12(a-1)-23]2的值;(2)求log2.56.25+lg0.01+ln√e-21+log23的值.试题及答案-解答题-云返教育

    • 试题详情

      (1)已知a=8,b=-2,求[a-
      1
      2
      b(ab-2)-
      1
      2
      (a-1)-
      2
      3
      ]2的值;
      (2)求log
      2.56.25+lg0.01+ln
      e
      -21+log23的值.

      试题解答


      见解析
      解:(1)原式=求[a-
      1
      2
      b(ab-2)-
      1
      2
      (a-1)-
      2
      3
      ]2=(a-
      1
      3
      ?b2)=a -
      2
      3
      ?b4
      将a=8,b=-2,代入上式得:8
      -
      2
      3
      ?(-2)4=2-2?24=22=4.
      (2)原式=log
      2.56.25+lg0.01+ln
      e
      -21+log23
      =2-2+
      1
      2
      -2×3
      1
      2
      -6=-
      11
      2
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