• 设f(x)={2ax,x≤1loga(x2-1),x>1且f(2√2)=1,则a= ;f(f(2))= .试题及答案-填空题-云返教育

    • 试题详情

      设f(x)=
      {
      2ax,x≤1
      loga(x2-1),x>1
      且f(2
      2
      )=1,则a=          ;f(f(2))=         

      试题解答


      7:6
      解:∵f(x)=
      {
      2ax,x≤1
      loga(x2-1),x>1

      ∴f(2
      2
      )=loga[(2
      2
      )2-1]
      =log
      a7,
      ∵f(2
      2
      )=1,
      ∴log
      a7=1,
      ∴a=7;
      ∴f(f(2))=f[log
      7(4-1)]
      =f(log
      73)
      =2×7
      log73
      =2×3=6.
      故答案为:7,6.
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