• 已经函数f(x)=2sinxcosx+sin2x-cos2x.(1)求f(x)递增区间;(2)求f(x)当x∈[0,]时的值域.试题及答案-解答题-云返教育

    • 试题详情

      已经函数f(x)=2sinxcosx+sin2x-cos2x.
      (1)求f(x)递增区间;
      (2)求f(x)当x∈[0,
      ]时的值域.

      试题解答


      见解析
      ∵f(x)=2sinxcosx+sin2x-cos2x
      =sin2x-cos2x
      =
      (cos()sin2x+sin()cos2x)
      =
      sin(2x
      (1)f(x)递增区间为2x
      k∈Z
      即递增区间为x∈[
      ]k∈Z)
      (2)当x∈[0,
      ]
      即2x
      ∈[]
      ∴f(x)
      min=sin()=-1
      f(x)
      max=sin()=
      即f(x)当x∈[0,
      ]时的值域为[-1,]
    MBTS ©2010-2016 edu.why8.cn