• 不查表求值:cos40°?cos80°+cos80°?cos160°+cos160°?cos40°.试题及答案-解答题-云返教育

    • 试题详情

      不查表求值:cos40°?cos80°+cos80°?cos160°+cos160°?cos40°.

      试题解答


      见解析
      解:原式=
      1
      2
      [cos120°+cos(-40°)+cos240°+cos(-80°)+cos200°+cos120°]
      =
      1
      2
      (-cos60°+cos40°-cos60°+cos80°-cos20°-cos60°)
      =
      1
      2
      [-
      3
      2
      +cos(60°-20°)+cos(60°+20°)-cos20°]
      =
      1
      2
      [-
      3
      2
      +cos60°cos20°+sin60°sin20°+cos60°cos20°-sin60°sin20°-cos20°]
      =
      1
      2
      [-
      3
      2
      +cos20°-cos20°]
      =-
      3
      4
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